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Diodes & Applications

16 دقيقة قراءة

Mansoura University
Mansoura University
Faculty of Computers and Information
Department of Information Technology
First Semester
Faculty of Computers and Information
Intro to Physics · Lesson 13
Diodes & Applications
Prepared by Muhammad Elsayed
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ملاحظات الدرس

Diodes & Applications

The PN junction

Put p-type and n-type silicon in contact and something useful happens at the boundary on its own, with no voltage applied.

  • Free electrons diffuse from the n side into the p side and recombine with holes, leaving uncovered ions behind.
  • Those two layers of fixed charge form the depletion region, and the field across it stops further diffusion.
  • Crossing that field costs energy, and the cost is the barrier potential: about 0.7 V for silicon and 0.3 V for germanium at 25 °C.
  • The p side is the anode, the n side is the cathode, and the symbol's arrow points the way conventional current flows.

Three bias conditions

  • No bias: the depletion region sits at its natural width and the net current is zero.
  • Forward bias, plus to the p side: the depletion region narrows, and once the applied voltage exceeds the barrier potential the diode conducts heavily.
  • Reverse bias, plus to the n side: the depletion region widens and only a tiny saturation current flows, until the reverse voltage reaches breakdown.

This is why the V-I characteristic is a near-flat line one way and a steep knee the other.

Working with diodes in a circuit

You almost never solve the exponential diode equation by hand. You pick a model.

  • Ideal model: a perfect switch, 0 V when on. Good for a quick sanity check.
  • Practical model: a 0.7 V drop when on. This is the one used throughout this course.
  • Complete model: adds the bulk resistance rd. Reserved for precision work.
  • Load-line analysis solves the circuit and the device together: draw the resistor's line across the diode's curve and read the Q point, VDQ and IDQ, where they cross.

For series and parallel configurations the method is always the same: decide whether each diode is on or off, replace it with its model, then solve what is left with Ohm and Kirchhoff.

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